DigitalVolcano Software Support

DigitalVolcano wrote:This should work

Regex

Code: Select all

.([0-9]{4})[0-9]{1,}

Replace

Code: Select all

.$1

Try it in the regex tester

You forgot to escape the . ;-)

I know this is an old topic buy maybe you are still looking?
should to what you want. Not sure if it's efficient. On long texts it potentially has to look at the whole text...

Hi!
I can think of two ways to do it. I'll describe both, just for educational purposes :-D

1. Matching groups:
You can replace

[oO](\d\d\d\d\d)

with

N$1

Here $1 refers to the first expression in brackets...

2. Lookahead
Replace
[oO](?=\d\d\d\d\d)

with

N

This one tells it to find [oO ...

I'm not associated with the program so I might be wrong, but both pdf and doc don't necessarily show words they contain in a plaintext view. New docx is actually a zip file, which means there is compression at work. PDF also does some weird stuff. TG does not parse the file, it just opens them. So a ...

Hi!
great fan of your software, I have the Pro version of Duplicate Cleaner and I often use TextCrawer to work on my extensive text collection...

I'm still using v2.5 cause last time I checked (been a while) there was only a pro version of 3... Now I noticed that there is also a free version of 3 ...

The easiest solution I can think of is this:
Replace
(?<=\do*)o
with
0

This uses the fact that you can ask what's in front of a place without having to match it. Therefore this matches all "o"s that have a digit followed by any amount of "o"s. Due to the fact that this \do+ is not actually ...